How can I call PHP functions by JavaScript?

05/23/2020 20:00:01

I am trying to call a PHP function from an external PHP file into a JavaScript script. My code is different and large, so I am writing a sample code here.

This is my PHP code:

<?php
function add($a,$b){
  $c=$a+$b;
  return $c;
}
function mult($a,$b){
  $c=$a*$b;
  return $c;
}

function divide($a,$b){
  $c=$a/$b;
  return $c;
}
?>

This is my JavaScript code:

<script>
  var phpadd= add(1,2); //call the php add function
  var phpmult= mult(1,2); //call the php mult function
  var phpdivide= divide(1,2); //call the php divide function
</script>

So this is what I want to do.

My original PHP file doesn't include these mathematical functions but the idea is same.

If some how it doesn't have a proper solution, then may you please suggest an alternative, but it should call values from external PHP.

Verified Answer (78 Votes)

04/02/2013 12:05:20

Yes, you can do ajax request to server with your data in request parameters, like this (very simple):

Note that the following code uses jQuery

jQuery.ajax({
    type: "POST",
    url: 'your_functions_address.php',
    dataType: 'json',
    data: {functionname: 'add', arguments: [1, 2]},

    success: function (obj, textstatus) {
                  if( !('error' in obj) ) {
                      yourVariable = obj.result;
                  }
                  else {
                      console.log(obj.error);
                  }
            }
});

and your_functions_address.php like this:

    <?php
    header('Content-Type: application/json');

    $aResult = array();

    if( !isset($_POST['functionname']) ) { $aResult['error'] = 'No function name!'; }

    if( !isset($_POST['arguments']) ) { $aResult['error'] = 'No function arguments!'; }

    if( !isset($aResult['error']) ) {

        switch($_POST['functionname']) {
            case 'add':
               if( !is_array($_POST['arguments']) || (count($_POST['arguments']) < 2) ) {
                   $aResult['error'] = 'Error in arguments!';
               }
               else {
                   $aResult['result'] = add(floatval($_POST['arguments'][0]), floatval($_POST['arguments'][1]));
               }
               break;

            default:
               $aResult['error'] = 'Not found function '.$_POST['functionname'].'!';
               break;
        }

    }

    echo json_encode($aResult);

?>
78

Answer #2 (35 Votes)

04/02/2013 11:46:27

Try This

<script>
  var phpadd= <?php echo add(1,2);?> //call the php add function
  var phpmult= <?php echo mult(1,2);?> //call the php mult function
  var phpdivide= <?php echo divide(1,2);?> //call the php divide function
</script>
35

Answer #3 (12 Votes)

11/25/2013 10:53:45

use document.write for example,

<script>
  document.write(' <?php add(1,2); ?> ');
  document.write(' <?php milt(1,2); ?> ');
  document.write(' <?php divide(1,2); ?> ');
</script>
12
3
Hack Hex uses Stack Exchance API by the Stack Exchange Inc. to scrape questions/answers under Creative Commons license.