Receive JSON POST with PHP

03/25/2020 18:30:02

I’m trying to receive a JSON POST on a payment interface website, but I can’t decode it.

When I print :

echo $_POST;

I get:

Array

I get nothing when I try this:

if ( $_POST ) {
    foreach ( $_POST as $key => $value ) {
        echo "llave: ".$key."- Valor:".$value."<br />";
    }
}

I get nothing when I try this:

$string = $_POST['operation'];
$var = json_decode($string);
echo $var;

I get NULL when I try this:

$data = json_decode( file_get_contents('php://input') );
var_dump( $data->operation );

When I do:

$data = json_decode(file_get_contents('php://input'), true);
var_dump($data);

I get:

NULL

The JSON format is (according to payment site documentation):

{
   "operacion": {
       "tok": "[generated token]",
       "shop_id": "12313",
       "respuesta": "S",
       "respuesta_details": "respuesta S",
       "extended_respuesta_description": "respuesta extendida",
       "moneda": "PYG",
       "monto": "10100.00",
       "authorization_number": "123456",
       "ticket_number": "123456789123456",
       "response_code": "00",
       "response_description": "Transacción aprobada.",
       "security_information": {
           "customer_ip": "123.123.123.123",
           "card_source": "I",
           "card_country": "Croacia",
           "version": "0.3",
           "risk_index": "0"
       }
    }
}

The payment site log says everything is OK. What’s the problem?

Answer #1 (464 Votes)

09/18/2013 13:30:28

Try;

$data = json_decode(file_get_contents('php://input'), true);
print_r($data);
echo $data["operacion"];

From your json and your code, it looks like you have spelled the word operation correctly on your end, but it isn't in the json.

EDIT

Maybe also worth trying to echo the json string from php://input.

echo file_get_contents('php://input');
464

Answer #2 (83 Votes)

09/15/2016 15:07:07

If you already have your parameters set like $_POST['eg'] for example and you don't wish to change it, simply do it like this:

$_POST = json_decode(file_get_contents('php://input'), true);

This will save you the hassle of changing all $_POST to something else and allow you to still make normal post requests if you wish to take this line out.

83
2
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